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29 Oct 2019, 01:45
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
87% (02:16) correct
13%
(02:41)
wrong
based on 97
sessions
History
Date
Time
Result
Not Attempted Yet
Company X sells a selection of products at various price points. Listed below are unit sales made for one particular day. How many unit sales on that day were greater than the mean sale price but less than the median sale price?
$50, $50, $97, $97, $97, $120, $155, $155, $155, $199, $199
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
$50, $50, $97, $97, $97, $120, $155, $155, $155, $199, $199
(A) 0
(B) 1
(C) 2
(D) 3
(E) 4
29 Oct 2019, 03:19
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Bunuel
Mean = 150 + (-100 - 100 - 53 - 53 -53 -30 + 5 + 5 + 5 + 49 + 49)/11 = 150 + (-389 + 113)/11 = 150 - 25.09 = $124.909
Median = $120
Number of unit sales on that day were greater than the mean sale price($124.909) but less than the median sale price ($120) = 0
IMO A
29 Oct 2019, 03:31
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Bunuel
There are total 11 product prices arranged in increasing order as $50, $50, $97, $97, $97, $120, $155, $155, $155, $199, $199.
So median is the 6th product price = 120$
For mean lets say assumed mean is 100$.
Real mean = 100+(-50-50-3-3-3+20+55+55+55+99+99)/11
= 100+((55-50)+(55-50)+(-9)+20+55+(200-2))/11
= 100+(5+5+-9+20+55+200-2)/11
= 100+(21+53+200)/11
= 100+(274)/11
= 100+24.909
= 124.909$
So, there are no sales above 124.909$ and below 120$ possible. Hence 0.
