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02 Nov 2019, 02:10
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
39% (02:51) correct
61%
(02:56)
wrong
based on 145
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Two persons A and B start from the opposite ends of a 450 km straight track and run to and from between the two ends. The speed of the first person is 25 m/s and the speed of other is 35 m/s. They continue their motion for 10 hours. How many times did they pass each other?
A. 1
B. 2
C. 3
D. 4
E. 5
A. 1
B. 2
C. 3
D. 4
E. 5
02 Nov 2019, 03:43
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jackfr2
Let us find the total distance traveled by both combined.
Combined speed = (25+35) or 60 m/s, which is same as \(\frac{60m}{\frac{hr}{60*60}}=\frac{60*60*60m}{hr}\) or 216kmph =>
In 10 hrs they will travel 216*10=2160km @ 216kmph.
The first time both meet, they cover a combined distance of 450km, that is 1 lap,
But next time they meet both cover a distance of 900km, that is they cover 2 laps.
Next they should meet after another 900kms or 450+900+900=2250, but they have traveled only 2160 in 10 hrs, so they do not meet 3rd time in 10 hrs.
Answer 2 times
B
General Discussion
02 Nov 2019, 03:41
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speed of first person=\(25*(\frac{18}{5})\)=90 kmph
speed of second person=\(35*(\frac{18}{5})\)=126 kmph
Time taken by them to meet first time= \(\frac{450}{216}\)= 2.x hours
Time taken by them to meet second time= \(2.x+(\frac{2*450}{216})\)=6.y hours
Time taken by them to meet third time= \(6.y+(\frac{2*450}{216})\)= 10.z hours >10
Hence, they passed each other 2 times.
speed of second person=\(35*(\frac{18}{5})\)=126 kmph
Time taken by them to meet first time= \(\frac{450}{216}\)= 2.x hours
Time taken by them to meet second time= \(2.x+(\frac{2*450}{216})\)=6.y hours
Time taken by them to meet third time= \(6.y+(\frac{2*450}{216})\)= 10.z hours >10
Hence, they passed each other 2 times.
jackfr2
