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Dillesh4096
Smith and Tom earn a combined profit of $4880 in their business and invest their share at 20% compounded annually at the same time. If the amount earned by Smith after 10 years is same as amount earned by Tom after 12 years. Find the amount invested by Smith.

A. $2880
B. $2640
C. $2520
D. $2440
E. $2000

Solution:

  • Tom's investment and Smit's investment equated in 12 and 10 years. So, the difference is 2 years.
  • First of all, this clearly means Smith's investment was more than Tom's. You can eliminate options D and E here

  • Because of the difference in 2 years, we can infer that \(\frac{Smith}{Tom}=(1.2)^2=1.44\)
  • So, we can write \(Smith+\frac{Smith}{1.44}=4880\) or \(Smith=2880\)

Hence the right answer is Option A

Hi Saquib,

Can you please elaborate on this part "Because of the difference in 2 years, we can infer that \(\frac{Smith}{Tom}\)=(1.2)^2=1.44"?

Thanks in advance. :)
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Dillesh4096
Smith and Tom earn a combined profit of $4880 in their business and invest their share at 20% compounded annually at the same time. If the amount earned by Smith after 10 years is same as amount earned by Tom after 12 years. Find the amount invested by Smith.

A. $2880
B. $2640
C. $2520
D. $2440
E. $2000

Solution:

  • Tom's investment and Smit's investment equated in 12 and 10 years. So, the difference is 2 years.
  • First of all, this clearly means Smith's investment was more than Tom's. You can eliminate options D and E here

  • Because of the difference in 2 years, we can infer that \(\frac{Smith}{Tom}=(1.2)^2=1.44\)
  • So, we can write \(Smith+\frac{Smith}{1.44}=4880\) or \(Smith=2880\)

Hence the right answer is Option A

Hi Saquib,

Can you please elaborate on this part "Because of the difference in 2 years, we can infer that \(\frac{Smith}{Tom}\)=(1.2)^2=1.44"?

Thanks in advance. :)

would love for an explanation as well
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chetan2u
Dillesh4096
Smith and Tom earn a combined profit of $4880 in their business and invest their share at 20% compounded annually at the same time. If the amount earned by Smith after 10 years is same as amount earned by Tom after 12 years. Find the amount invested by Smith.

A. $2880
B. $2640
C. $2520
D. $2440
E. $2000


Let the amount by smith be S, so by Tom it is 4880-S..
Smith : Amount after 10 years = \(S(1+\frac{20}{100})^{10}\)
Tom : Amount after 12 years = \((4880-S)(1+\frac{20}{100})^{12}\)

As both amounts are same....
\(S(1+\frac{20}{100})^{10}=(4880-S)(1+\frac{20}{100})^{12}.........S=(4880-S)(1+\frac{20}{100})^{2}=(4880-S)*(\frac{6}{5})^2...........S+\frac{36S}{25}=4880*\frac{36}{25}.......\)..
\(\frac{61S}{25}=4880*\frac{36}{25}...........S=4880*\frac{36}{25}*\frac{25}{61}=80*36=2880\)

A
The question states that the profits are the same, not the amount. so why is this right?
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ChandlerBong
SaquibHGMATWhiz
Dillesh4096
Smith and Tom earn a combined profit of $4880 in their business and invest their share at 20% compounded annually at the same time. If the amount earned by Smith after 10 years is same as amount earned by Tom after 12 years. Find the amount invested by Smith.

A. $2880
B. $2640
C. $2520
D. $2440
E. $2000

Solution:

  • Tom's investment and Smit's investment equated in 12 and 10 years. So, the difference is 2 years.
  • First of all, this clearly means Smith's investment was more than Tom's. You can eliminate options D and E here

  • Because of the difference in 2 years, we can infer that \(\frac{Smith}{Tom}=(1.2)^2=1.44\)
  • So, we can write \(Smith+\frac{Smith}{1.44}=4880\) or \(Smith=2880\)

Hence the right answer is Option A

Hi Saquib,

Can you please elaborate on this part "Because of the difference in 2 years, we can infer that \(\frac{Smith}{Tom}\)=(1.2)^2=1.44"?

Thanks in advance. :)

Sure. Here it is.

Smith's amount in 10 years = Tom's amount in 12 years

\(⇒Smith\times (1.2)^{10}=Tom\times (1.2)^{12}\)

\(⇒Smith=Tom\times (1.2)^2\)

\(⇒\frac{Smith}{Tom}=(1.2)^2=1.44\)
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