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Quote:

In the figure shown, O is the centre of the circle. What is the value of x+y+z?

A. 104
B. 112
C. 180
D. 188
E. 196

2x=180-100
x=40
y=180-108-x
y=72-40=32
z=180-2y
z=180-64=116
x+y+z=40+32+116=188

Ans (D)
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A = B= x (as OA and OB are radius)
2x + 100 = 180
X = 40,
X+Y+108 = 180,
Y = 180-148 = 32
2Y + Z = 180, As OB = OC,
Z = 180-64 =116
X+Y+Z = 116+32+40 =188.

Imo. D
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tingle abo is isosceles as ob and oa are radius of circle , so angle x=40
AT ia 180 so ,Y= 180-40-108=32 , again triangle OBC IS isosceles triangle Z= 180-32-32=116
X+Y+Z=40+32+116=188
ANS:D

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From the figure, AO=OB=radius of the circle. This implies, triangle AOB is isosceles, therefore angle OAB (x)= angle ABO.
Hence 2x+100=180 and x=40

Also from the figure, x+y+108=180
which means 40+108+y=180, hence y=180-148=32

OC=OB=radius of the circle. This also implies that triangle BOC is isosceles, therefore, angle OCB=angle OBC (y)
Hence 2y+z=180, hence z+64=180
thus z=180-64=116
x+y+z=40+32+116 = 188

The answer is therefore option D.
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