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22 Nov 2019, 03:35
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
82% (02:15) correct
18%
(02:41)
wrong
based on 260
sessions
History
Date
Time
Result
Not Attempted Yet
A certain class of 90 students took a typing proficiency test. The average (arithmetic mean) score of the students who passed the test was 84, and the average score of the students who failed the test was 60. If the average score of all students was 80, how many students passed the test?
A. 15
B. 20
C. 42
D. 70
E. 75
A. 15
B. 20
C. 42
D. 70
E. 75
Archit3110
22 Nov 2019, 04:36
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p+f=90
total score = 90*80 ; 7200
84*p+60*(90-p) = 7200
p = 75
IMO E
total score = 90*80 ; 7200
84*p+60*(90-p) = 7200
p = 75
IMO E
Bunuel
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Location: Singapore
Concentration: Finance, General Management
Schools: SMU MAF "21 (A)
GMAT 1: 620 Q46 V30
WE:Analyst (Commercial Banking)
03 Jan 2020, 22:47
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Total score of all students = 80 * 90 = 7200
Since the avg. score of students who passed the test is 84, the number students who passed the test must end with a 5.
Therefore, only option A. 15 or option E.75 is possible.
We can rule out 15 as it would shift the avg. away from 80.
Ans: E. 75
Since the avg. score of students who passed the test is 84, the number students who passed the test must end with a 5.
Therefore, only option A. 15 or option E.75 is possible.
We can rule out 15 as it would shift the avg. away from 80.
Ans: E. 75
