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We have two groups, one with a 35% average, one with an 11% average. If the groups were equal in size, then combined they would have a (35+11)/2 = 23% average. But the 11% group is very slightly bigger than the 35% group, so the overall average will be slightly closer to 11%. Only answer B makes much sense, though I suppose if you were undecided between A and B you might do a bit of calculation.

Could you please explain "so the overall average will be slightly closer to 11%"?

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TSneha

Could you please explain "so the overall average will be slightly closer to 11%"?

It's just a weighted average problem. Using simpler numbers, say you mix a 20% salt solution with a 40% salt solution. If you use equal quantities of each, the mixture will be 30% salt. If you use more of the 20% solution, the resulting mixture will be closer to 20% salt (so will be between 20% and 30% salt). The ratio of the amounts you use determine where the overall average ends up.
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Shortcut:
Ratio of people in both the groups = 240:300 = 4:5
Now you are mixing them.
Therefore by weighted avg approach

No of people choosing internet as an option = ((35*4) +(11*5))/9
= 21.7

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Bunuel

Which of the following is closest to the percent of all the people survey who indicated the Internet as their preferred method to obtain news?

A. 18.8%
B. 21.7%
C. 23.0%
D. 33.3%
E. 46.0%

Because the number of individuals in each of the two groups is different (240 versus 300), we have to calculate two separate values. For age group 20 to 49, we see that 240 x 0.35 = 84 individuals prefer the internet for obtaining news; for age group 50 and older, we see that 300 x 0.11 = 33 individuals prefer the internet for obtaining news. Therefore, the overall percent who prefer the internet is:

(0.35 x 240 + 300 x 0.11)/(240 + 300) = 117/540 ≈ 0.217 = 21.7%

Answer: B
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