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19 Dec 2019, 11:13
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (01:57) correct
22%
(02:09)
wrong
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Integer A is a three-digit integer in which all the three digits are the same. Integer B is a two-digit integer in which both digits are the same, but A and B have no digits in common. If the difference of A - B produces an integer in which none of the digits match any of the digits A or B, which of the following cannot be the value of A?
(A) 666
(B) 444
(C) 999
(D) 777
(E) 555
(A) 666
(B) 444
(C) 999
(D) 777
(E) 555
19 Dec 2019, 13:06
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If max value of A is 999 then minus B.... XX, then max number for XX is 88, so the result is 911 or higher. But first digit of the result cannot be 9 since A is 999 and no digits can be the same.
IMHO
C
IMHO
C
19 Dec 2019, 13:31
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AAA (First integer)
-BB (Second Integer)
===
XYZ (The result of First Integer - Second Integer)
Main Condition: The Final result (which is the result of AAA-BB) CAN NOT have any digit of A or B.
The second Integer can be 11,22,33,44................99.
Think about C: Whatever (11,22,33,44................99) you subtract from 999, the first digit will still be 9 but the question says the Final result(which is the result of AAA-BB) CAN NOT have any digit of A or B.
-BB (Second Integer)
===
XYZ (The result of First Integer - Second Integer)
Main Condition: The Final result (which is the result of AAA-BB) CAN NOT have any digit of A or B.
The second Integer can be 11,22,33,44................99.
Think about C: Whatever (11,22,33,44................99) you subtract from 999, the first digit will still be 9 but the question says the Final result(which is the result of AAA-BB) CAN NOT have any digit of A or B.
