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\(3^2+6^2+9^2+12^2+15^2+...+27^2 = 3^2 * ( 1^2 + 2^2 + 3^2 + ... + 9^2) = 9*285 = 2565\)
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1^2 +2^2 +3^2 +... +9^2 = 285
3^2*(1^2 +2^2 +3^2 +... +9^2) = 3^2*285
3^2 +6^2 +9^2 +... +27^2 = 9*285 = 2565

Final answer is (B)

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If \(1^2+2^2+3^2+...+9^2=285\), \(3^2+6^2+9^2+12^2+15^2+...+27^2=?\)

(A) 855
(B) 2,565
(C) 7,695
(D) 23,085
(E) 69,255

\(1^2+2^2+3^2+...+9^2=285\)
\(3^2+6^2+9^2+12^2+15^2+...+27^2\)
\((3.1)^2+(3.2)^2+(3.3)^2+(3.4)^2+(3.5)^2+...+(3.9)^2\)
\(3^2(1^2+2^2+3^2+4^2+5^2+...+9^2)\)
9 * 285 = 2565

Answer B.
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If \(1^{2}+2^{2}+3^{2}+...+9^{2}=285\) ,
--> \(3^{2}+6^{2}+9^{2}+12^{2}+15^{2}+...+27^{2}\) =?

--> \(3^{2}+6^{2}+9^{2}+12^{2}+15^{2}+...+27^{2}\)= \(3^{2}\)* (\(1^{2}+2^{2}+3^{2}+...+9^{2\))=9*(285)= 2565

The answer is B.
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Given sum of squares = 285
And for given expression we can rewrite as 9*285= 2565 IMOB

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We are given that,3^2 + 6^2 + 9^2 + 12^2 + 15^2 +……………………..+27^2
= 1 x 3^2 + 2^2 x 3^2 + 3^2 x 3^2 + 3^2 x 4^2 + 3^2 x 5^2 + ……………+ 3^2 x 9^2
=3^2(1 + 2^2 + 3^2 + 4^2 + 5^2 + ……………+ 9^2)
= 9 x 285(1 + 2^2 + 3^2 + 4^2 + 5^2 + ……………+ 9^2 = 285)
= 2,565(B)
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1^2+2^2+3^2+...+9^2=285
3^2+6^2+9^2+12^2+15^2+...+27^2 = 3^2(1^2+2^2+3^2+...+9^2) = 9*285 = 2565

The answer is B.
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