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08 Jan 2020, 10:18
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
29% (01:40) correct
71%
(01:18)
wrong
based on 107
sessions
History
Date
Time
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Not Attempted Yet
A ticket is selected at random from 50 tickets numbered 00, 01, 02, ……, 49. Find the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero.
A. 1/14
B. 1/10
C. 1/11
D. 1/50
E. 1/25
Posted from my mobile device
A. 1/14
B. 1/10
C. 1/11
D. 1/50
E. 1/25
Posted from my mobile device
Updated on: 08 Jan 2020, 22:13
Originally posted by rajatchopra1994 on 08 Jan 2020, 21:31.
Last edited by rajatchopra1994 on 08 Jan 2020, 22:13, edited 1 time in total.
Last edited by rajatchopra1994 on 08 Jan 2020, 22:13, edited 1 time in total.
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Dillesh4096
Explanation:
Event A: When Sum is 8
Favorable Outcome: 08, 17, 26, 35, 44
Event B: When Product is Zero.
Fav. Outcome : 00, 01, 02,........09, 10, 20, 30, 40
A∩B = 08 (only One Case Common in Event A & B)
Required Probability = P(A/B) = P(A∩B)/P(B) = 1/50 / 14/50
=1/14
IMO-A
08 Jan 2020, 22:05
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Dillesh4096
No. of favourable outcomes=08 (product of digits must also be zero so this is the only case)
=>1/50
IMO answer choice is D
