For all numbers x and y the definition of the operation ♦ is x♦ y=xy(x

Question

For all numbers  x  and  y  the definition of the operation  ♦  is  x♦ y=xy(x+4) . If  (-6) ♦ a = -60,  then what is the value of  a  ?

A. -20
B. -5
C. 2.5
D. 5
E. 10

KarishmaB · Answer

x♦ y=xy(x+4)

(-6) ♦ a = -60 = (-6)a(-6 + 4) = 12a

a = -5

Answer (B)

Jawad001 · Answer

We are given 
 • x♦y = xy(x+4)
 • (−6) ♦a=−60
Required: a = ?

• (−6) ♦a=−60
or, (-6)a (-6 + 4) = -60
or, (-6a) *(-2) = -60
or, 12a = -60
or, a = -5

Answer: (B)

ScottTargetTestPrep · Answer

(-6)*a = -60

-6a(-6 + 4) = -60

36a - 24a = -60

12a = -60

a = -5

Answer: B

BrushMyQuant · Answer

Given that  x♦ y=xy(x+4)  and  (-6) ♦ a = -60,  and we need to find the value of a

To find (-6) ♦ a we need to compare what is before and after ♦ in (-6) ♦ a and x♦ y

=> We need to substitute x with -6 and y with a in x♦ y to get the value of (-6) ♦ a

=>  -6♦ a=-6*a(-6+4)  = -6a*-2 = 12a = -60 (given)
=> a =  \frac{-60}{12}  = -5

So,  Answer will be B 
Hope it helps!

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https://www.youtube.com/watch?v=b7JoMX0gk8M

naveeng15 · Answer

-6*a = 60
-6(a) (-6+4) = 60 
Since x*y = xy(x+4)

Which implies 
12a = 60
a= 5

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naveeng15 · Answer

x♦y=xy(x+4)x♦y=xy(x+4)

(−6)♦a=−60=(−6)a(−6+4)=12a(−6)♦a=−60=(−6)a(−6+4)=12a

a = -5

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