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Updated on: 04 Nov 2024, 01:22
Originally posted by QuantMadeEasy on 18 Feb 2020, 04:49.
Last edited by QuantMadeEasy on 04 Nov 2024, 01:22, edited 2 times in total.
Last edited by QuantMadeEasy on 04 Nov 2024, 01:22, edited 2 times in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
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Question Stats:
70% (01:57) correct
30%
(02:13)
wrong
based on 257
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If 1 cup of water is added to a 5-cup mixture that is \(\frac{2}{3}\) salt and \(\frac{1}{3}\) water, what percent of the 6-cup mixture is salt?
A. 20%
B. 25%
C. 33.33%
D. 55.56%
E. 66.67%
Study from the best self learning GMAT quant course:
https://www.udemy.com/course/best-gmat- ... 37602183BB
A. 20%
B. 25%
C. 33.33%
D. 55.56%
E. 66.67%
Study from the best self learning GMAT quant course:
https://www.udemy.com/course/best-gmat- ... 37602183BB
18 Feb 2020, 15:08
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(2/3) * 5 / 6 = 5/9=0.55555555
Posted from my mobile device
Posted from my mobile device
18 Feb 2020, 15:15
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The chemistry principle of C*V initial = C*V Final can be applied to this problem:
(\(\frac{2}{3}\))*(5) = C Final *6
\(\frac{10}{3}\)* \(\frac{1}{6}\) = C Final
\(\frac{10}{18}\) = 0.555555 = 55.5555% = C Final
Ans= D
(\(\frac{2}{3}\))*(5) = C Final *6
\(\frac{10}{3}\)* \(\frac{1}{6}\) = C Final
\(\frac{10}{18}\) = 0.555555 = 55.5555% = C Final
Ans= D
