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given
a*b/100= c
c/100 * d= e
a=x*e/100
x=a*100/e
substitute a & e values
we get

\(\frac{1000000}{bd}\)
IMO E


Bunuel
If a, b, c, d, and e are all greater than 0 and a percent of b is c and c percent of d is e, then a is what percent of e?


A. \(\frac{bd}{1000}\)

B. \(\frac{10000}{bd}\)

C. \(10000 bd\)

D. \(\frac{bd}{1000}\)

E. \(\frac{1000000}{bd}\)




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Not to get lost in this percent mess, I've tried to pick comfortable numbers.
Let a=10 and b=100 then c=10
To have the diversity let d=200 then e=20

We are asked what percent is 10 of 20? it's 50%

let's start checking the answer choices but look A, C and D can be easily dropped, dont waste even a second

After testing B and E, E is the correct answer

IMO
Ans: E


The answer is
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