If (10)^9 + 2(11)^1(10)^8 + 3(11)^2(10)^7 + … + 10(11)^9 = k(10)^9

Question

Competition Mode Question

If  (10)^9 + 2(11)^1(10)^8 + 3(11)^2(10)^7 + … + 10(11)^9 = k(10)^9 , then k is equal to

A. 121/10 
B. 441/100 
C. 100 
D. 110
E. 120

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freedom128 · Accepted Answer

10^9 * { 1+ 2*(1.1)^1 + 3*(1.1)^2 +... + 10*(1.1)^9 } = 10^9 * k

Estimate lower-bound value of k: 
= 10^9 * { 1+ 2*(1)^1 + 3*(1)^2 +... + 10*(1)^9 } 
= 10^9 * {1+ 2+ ...+10} 
= 10^9 * 55 = 10^9 * k
k > 55 --->  eliminate choices (A) 12.1 and (B) 44.1

Estimate reasonable value of k:
= 10^9 * { 1+ 2*(1)^1 + 3*(1)^2 + ... +10*(1)^9} * 1.1^6
= 10^9 * 55 * ~1.6
= 10^9 * ~88 = 10^9 * k
k is close to 100

Thus, FINAL ANSWER IS (C)

nick1816 · Answer

S=k*10^9= 10^9+2*11*10^8+3*11^2*10^7+........+10*11^9 ........(1)

(\frac{11}{10})S= 11*10^8+2*11^2*10^7+........+9*11^9+11^{10} ......(2)

Subtract (1) from (2)

\frac{S}{10} = 11^{10}-

S/10 = 11^{10}-

\frac{S}{10} = 11^{10} -

S= 10^{11}

k*10^9= 10^{11}

k= 10^2 = 100

Thakurdas · Answer

I have calculated the whole log. It comes down to 10 to the power 11. So the answer should be C. But do they ask such questions in GMAT? If they do, there must be some way of doing it within 2 minutes which I cannot even begin to search for!

unraveled · Answer

If  (10)^9+2(11)^1(10)^8+3(11)^2(10)^7+…+10(11)^9=k(10)^9 , then k is equal to

A. 121/10
B. 441/100
C. 100
D. 110
E. 120
Multiplying given equation's both sides by  10^{-9} 
 (10)^9*10^{-9} + 2(11)^1(10)^8*10^{-9} + 3(11)^2(10)^7*10^{-9} + 4(11)^3(10)^6*10^{-9} + 5(11)^4(10)^5*10^{-9} + 6(11)^5(10)^4*10^{-9}+  
 + 7(11)^6(10)^3*10^{-9} + 8(11)^7(10)^2*10^{-9} + 9(11)^8(10)^1*10^{-9} + 10(11)^9*10^{-9} = k(10)^9*10^{-9}

1 + 2*11*10^{-1} + 3(11)^2*10^{-2} + 4(11)^3*10^{-3} + 5(11)^4*10^{-4} + 6(11)^5*10^{-5} + 7(11)^6*10^{-6}+ 
 + 8(11)^7*10^{-7} + 9(11)^8*10^{-8} + 10(11)^9*10^{-9} = k

1 + 2*1.1^1 + 3*1.1^2 + 4*1.1^3 + 51.1^4 + 6*1.1^5 + 7*1.1^6 + 8*1.1^7 + 9*1.1^8 + 10*1.1^9 = k

Solving for k gives ~ 100
(There must be a better way to solve it)

Answer C.

lacktutor · Answer

If  (10)^9+2 (11)^{1}(10)^{8}+3 (11)^{2}(10)^{7}+…+10 (11)^{9}=k (10)^{9} , then k is equal to

10^9*( 1 +2 (\frac{11}{10})+3 (\frac{11}{10})^{2}+…+10 (\frac{11}{10})^{9}=k (10)^{9}

k= 1 +2 (\frac{11}{10})+3 (\frac{11}{10})^{2}+…+10 (\frac{11}{10})^{9} 
---------------------------------------------------------------------------------------------------------------------------------------------
--> multiply both sides by  \frac{11}{10} :
 k(\frac{11}{10})= (\frac{11}{10}) + 2(\frac{11}{10})^{2} + 3(\frac{11}{10})^{3} +...+ 10(\frac{11}{10})^10

And subtract  k  from  k(\frac{11}{10}) :

k(\frac{11}{10} -1)= -1 -( (\frac{11}{10}) + (\frac{11}{10})^{2} + (\frac{11}{10})^{3} +...+ (\frac{11}{10})^{9} ) + 10(\frac{11}{10})^{10} 
---------------------------------------------------------------------------------------------------------------------------------------------
 (\frac{11}{10}) + (\frac{11}{10})^{2} + (\frac{11}{10})^{3} +...+ (\frac{11}{10})^{9}  - geometric sequence

Sum = \frac{(\frac{11}{10})*(\frac{11}{10})^9 -1)}{(\frac{11}{10}-1)}= 11* (\frac{11}{10})^9 -1)

---------------------------------------------------------------------------------------------------------------------------------------------
 k(\frac{11}{10} -1)= -1 - \frac{11^{10}}{10^{9}} +11 + \frac{11^{10}}{10^{9}}= 10

k (\frac{1}{10}) = 10 
 k =100

Answer (C)

ScottTargetTestPrep · Answer

Since 11 = 1.1 x 10, we can rewrite the left hand side of the equation as:

10^9 + 2(1.1 x 10)(10^8) + 3(1.1^2 x 10^2)(10^7) + … + 10(1.1^9 x 10^9) = k(10^9)

10^9 + 2(1.1)(10^9) + 3(1.1^2)(10^9) + … + 10(1.1^9 )(10^9) = k(10^9)

Dividing the equation by 10^9, we have:

1 + 2(1.1) + 3(1.1)^2 + … + 10(1.1^9) = k → Eq. 1

We need to find the value of k. Without a calculator, we can multiply the equation by 1.1 to obtain:

1.1 + 2(1.1)^2 + 3(1.1)^3 + … + 10(1.1^10) = 1.1k → Eq. 2

Subtracting Eq. 2 from Eq. 1 (by combining terms with the same powers of 1.1), we have:

1 + 1.1 + 1.1^2 + 1.1^3 + … + 1.1^9 - 10(1.1^10) = -0.1k → Eq. 3

Now we see that all the terms (except the last term) form a geometric sequence (notice that the first term 1 can be written as 1.1^0).

Recall that the sum of a finite geometric series is:

S_n = a_1 * (1 - r^n) / (1 - r)

where a_1 is the first term, n is the number of terms and r is the common ratio.

So the sum of the 10 positive terms (i.e., 1, 1.1, 1.1^2, …, 1.1^9) is:

S_10 = 1(1 - 1.1^10)/(1 - 1.1) = (1 - 1.1^10)/(-0.1)

Substituting this back into Eq. 3, we have:

(1 - 1.1^10)/(-0.1) - 10(1.1^10) = -0.1k

Multiply the above equation by -0.1, we have:

1 - 1.1^10 + 1.1^10 = 0.01k

1 = 0.01k

100 = k

Answer: C

Kinshook · Answer

If  (10)^9 + 2(11)^1(10)^8 + 3(11)^2(10)^7 + ... + 10(11)^9 = k(10)^9 , then k is equal to

(10)^9 + 2(11)^1(10)^8 + 3(11)^2(10)^7 + ... + 10(11)^9 = k(10)^9

Dividing the expression by 10^9

k = 1 + 2(11/10) + 3(11/10)^2 + .... + 10(11/10)^9
11k/10 = 11/10 + 2(11/10)^2 + ..... 10(11/10)^10

k - 11k/10 = 1 + (11/10) + (11/10)^2 + ... + (11/10)^9 - 10(11/10)^10
-k/10 = {(11/10)^10-1}/{11/10-1} - 10(11/10)^10 = 10{(11/10)^10 - 1} - 10(11/10)^10 = - 10
k = 100

IMO C

If (10)^9 + 2(11)^1(10)^8 + 3(11)^2(10)^7 + … + 10(11)^9 = k(10)^9

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GMAT Problem Solving (PS) Questions

If (10)^9 + 2(11)^1(10)^8 + 3(11)^2(10)^7 + … + 10(11)^9 = k(10)^9

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