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13 Mar 2020, 07:57
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
68% (02:04) correct
32%
(02:11)
wrong
based on 325
sessions
History
Date
Time
Result
Not Attempted Yet
The length of a certain rectangle is a multiple of 18, and the width of the rectangle is a multiple of 12. Which of the following CANNOT be the perimeter of the rectangle?
(A) 60
(B) 72
(C) 84
(D) 96
(E) 108
(A) 60
(B) 72
(C) 84
(D) 96
(E) 108
A) 60 = 2*30 = 2( 18+12)
C) 84 = 2*42 = 2( 18+12*2)
D) 96 = 2*48 = 2( 18*2 + 12)
E) 108 = 2*54 = 2( 18+ 12*3)
B) 72 = 2*36 cannot be the perimeter of the rectangle.
Answer (B)
Posted from my mobile device
C) 84 = 2*42 = 2( 18+12*2)
D) 96 = 2*48 = 2( 18*2 + 12)
E) 108 = 2*54 = 2( 18+ 12*3)
B) 72 = 2*36 cannot be the perimeter of the rectangle.
Answer (B)
Posted from my mobile device
yashikaaggarwal
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13 Mar 2020, 08:15
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OA is B
Length= 18x { 18,36,54...}
Width= 12y { 12,24,36,48...}
Perimeter= 2(l+w)
Put L= 18 and W= 12
2(18+12)=60
2(18+24)=84
2(36+12)=96
2(18+36)=108
2(36+24)=120
.
.
.
Among all the options given only option B is not among the perimeter.
So OA is B
Posted from my mobile device
Length= 18x { 18,36,54...}
Width= 12y { 12,24,36,48...}
Perimeter= 2(l+w)
Put L= 18 and W= 12
2(18+12)=60
2(18+24)=84
2(36+12)=96
2(18+36)=108
2(36+24)=120
.
.
.
Among all the options given only option B is not among the perimeter.
So OA is B
Posted from my mobile device
