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Bunuel
How many odd numbers are there from 50 to 450 with only the digits 0, 1, 2, 3, 4, or 5, where the repetition of these digits is allowed?

A. 54
B. 72
C. 78
D. 106
E. 111

2 digit numbers from 50 = 1*3 = 3 [Ten's digit = {1}, Unit's digit = {1, 3, 5,}]

3 digit numbers from 100 - 399 = 3*6*3 = 54 [Hundred's digit = {1, 2, 3}, Ten's digit = {0, 1, 2, 3, 4, 5}, Unit's digit = {1, 3, 5,}]

3 digit numbers from 400 - 450 = 1*5*3 = 15 [Hundred's digit = {4}, Ten's digit = {0, 1, 2, 3, 4}, Unit's digit = {1, 3, 5,}]

Total possible digits = 3 + 54 + 15 = 72

Option B
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Kindly see the attachment.

B - 72
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