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19 Mar 2020, 22:38
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
94% (00:31) correct
6%
(00:52)
wrong
based on 81
sessions
History
Date
Time
Result
Not Attempted Yet
Which of the following is a prime factorization of 144?
(A) \(2^4 * 3^2\)
(B) \(4 * 3^3\)
(C) \(2^3 * 12\)
(D) \(2^2 * 3 * 5\)
(E) \(2 * 3^2 * 4\)
(A) \(2^4 * 3^2\)
(B) \(4 * 3^3\)
(C) \(2^3 * 12\)
(D) \(2^2 * 3 * 5\)
(E) \(2 * 3^2 * 4\)
21 Mar 2020, 13:45
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144 = 12*12 = 2*2*3*2*2*3 = 2^4 * 3^2
c
c
22 Mar 2020, 08:16
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Solution
To find
We need to determine
- • The prime factorization of 144
Approach and Working out
We can express the number 144 in different ways – ultimately, we will end up getting the same result as prime factorized form
- • \(144 = 16 * 9 = 2^4 * 3^2\)
• \(144 = 12 * 12 = 2^2 * 3 * 2^2 * 3 = 2^4 * 3^2\)
• \(144 = 2 * 72 = 2 * 2 * 36 = 2 * 2 * 2 * 18 = 2 * 2 * 2 * 2 * 9 = 2 * 2 * 2 * 2 * 3 * 3 = 2^4 * 3^2\)
Thus, option A is the correct answer.
Correct Answer: Option A
