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24 Mar 2020, 01:22
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (02:25) correct
23%
(02:42)
wrong
based on 79
sessions
History
Date
Time
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Not Attempted Yet
Attachment:
14.jpg [ 18.3 KiB | Viewed 3825 times ]
Circle O, as shown in the figure above, has diameters of DB and AC and has a circumference of 9. What is the length of minor arc BC?
(A) 4
(B) 11/3
(C) 7/2
(D) 13/4
(E) 3
26 Mar 2020, 08:43
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since OA = OB
Angle OAB = Angle OBA = 70
Angle BOC = Sum of 2 interior opposite angles = 70 + 70 = 140
Arc BC = (140/360) * 9 = 7/2
Angle OAB = Angle OBA = 70
Angle BOC = Sum of 2 interior opposite angles = 70 + 70 = 140
Arc BC = (140/360) * 9 = 7/2
SajjadAhmad
Archit3110
Major Poster
26 Mar 2020, 09:32
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SajjadAhmad
we have
∆AOB ; angle A= angle B = 70
and angle AOB = 40
so angle BOC=140
also radius of circle ; 2*pi*r = 9 ; r= 4.5/pi
so length of minor arc BC ; 140/360 * 2*pi * 4.5*1/pi
solve we get 7/2
IMO C
