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22 Apr 2020, 00:16
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C
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Difficulty:
35%
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Question Stats:
75% (02:07) correct
25%
(02:23)
wrong
based on 129
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Suppose N and 4N each represent a three digit positive integer, and that the sum of the digits of N is 12. What is the greatest possible value of 4N?
(A) 732
(B) 846
(C) 984
(D) 1203
(E) 1512
(A) 732
(B) 846
(C) 984
(D) 1203
(E) 1512
firas92
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22 Apr 2020, 00:30
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Since N is an integer, 4N is a multiple of 4 and 4N is a three digit integer (4N is at least 400 and at most 996)
Eliminate (B) (D) & (E)
4N can be 732 and 984 and so its greatest possible value is 984
Answer is (C)
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Eliminate (B) (D) & (E)
4N can be 732 and 984 and so its greatest possible value is 984
Answer is (C)
Posted from my mobile device
GraemeGmatPanda
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Updated on: 22 Apr 2020, 07:21
Originally posted by GraemeGmatPanda on 22 Apr 2020, 01:49.
Last edited by GraemeGmatPanda on 22 Apr 2020, 07:21, edited 1 time in total.
Last edited by GraemeGmatPanda on 22 Apr 2020, 07:21, edited 1 time in total.
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Another way of working this out is to plug numbers. Since the math is quite simple it's possible to reach the answer very quickly.
Looking for the greatest possible 4N is equivalent to looking for the greatest possible N
We know that 4N is a 3 digit number therefore N < 250. The highest of which will be in the form of 24X with X 0-9
The only other constraint is that the sum of digits is 12, therefore 246 is by definition the highest solution.
4N = 4 x 246 = 984
Answer (C) 984
Looking for the greatest possible 4N is equivalent to looking for the greatest possible N
We know that 4N is a 3 digit number therefore N < 250. The highest of which will be in the form of 24X with X 0-9
The only other constraint is that the sum of digits is 12, therefore 246 is by definition the highest solution.
4N = 4 x 246 = 984
Answer (C) 984
