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Bunuel
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Let B take 'x' hours to do the job working alone. Then A alone will take (x-4) hours.
A and B will take 1/(x-4) and 1/x of the job respectively in 1 hour. Working together, they can complete {1/(x-4) + 1/x} of the job in 1 hour. It is given that together they can the full job in 288 minutes (25/4) hrs. Therefore:
(24/5) {1/(x-4) + 1/x} = 1....> 1/(x-4) + 1/x = 5/24....> (2x-4)/x(x-4) = 5/24....> 5x^2-68x+4*24 = 0....> 5x^2-60x-8x-4*24 = 0
5x(x-12)-8(x-12) = 0....> (x-12)(5x-8)=0. So, x is equal to 12 or 8/5 hrs. It cannot be the latter since that would mean A does the work in -(12/5) hrs.
B alone would take 12 hours to complete the job. ANS: D
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sahylsharma
Can somebody please explain the solution of this in detail ??


start with answer choices:

D

if B takes 12
A takes 8

amount of work done by A and B together - 12+8/12*8 = 5/24

if they cover 5 parts of work in 60 min
how much work done for 24 parts
you get 288
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