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23 Apr 2020, 16:13
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
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Question Stats:
41% (02:29) correct
59%
(02:55)
wrong
based on 112
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In a factory, one machine produces only nuts at the rate of 100 nuts per minute and needs to be cleaned for 5 minutes after production of every 1000 nuts. Another
machine produces only bolts at the rate of 75 bolts per minute and needs to be cleaned for 10 minutes after production of every 1500 bolts. If both the machines start production at the same time, what is the minimum duration required for producing 9000 pairs of nuts and bolts ?
(a) 130 minutes
(b) 135 minutes
(c) 170 minutes
(d) 180 minutes
(e) None of these
machine produces only bolts at the rate of 75 bolts per minute and needs to be cleaned for 10 minutes after production of every 1500 bolts. If both the machines start production at the same time, what is the minimum duration required for producing 9000 pairs of nuts and bolts ?
(a) 130 minutes
(b) 135 minutes
(c) 170 minutes
(d) 180 minutes
(e) None of these
23 Apr 2020, 19:41
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As machine producing bolts is slower so it produces 1500 bolts in 30 minutes. So 9000 bolts in 30×6=180 but last 10 minutes break will not be taken so 180-10=170.
Option C is the answer.
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Option C is the answer.
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23 Apr 2020, 20:15
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Machine A: produces nuts at the rate of 100 nuts per minute and needs to be cleaned for 5 minutes after the production of every 1000 nuts.
hence it can work continuously for 10 min to produce 1000 nuts, then needs 5 min break. So, in 15 min: 1000 Nuts.
Hence, to produce 9000 nuts, time taken = (9000/1000)*15 -5(last cleaning cycle need not be included in production time) = 130 min
Machine B: produces nuts at the rate of 75 bolts per minute and needs to be cleaned for 10 minutes after the production of every 1500 nuts.
hence it can work continuously for 20 min to produce 1500 nuts, then needs 10 min break. So, in 30 min : 1500 Bolts.
Hence, to produce 9000 bolts, time taken = (9000/1500)*30 -10(last cleaning cycle need not be included in production time) = 170 min
To produce the 9000 pairs of nuts and bolts: max of time taken by individual machines to be taken = 170 min
Answer C
hence it can work continuously for 10 min to produce 1000 nuts, then needs 5 min break. So, in 15 min: 1000 Nuts.
Hence, to produce 9000 nuts, time taken = (9000/1000)*15 -5(last cleaning cycle need not be included in production time) = 130 min
Machine B: produces nuts at the rate of 75 bolts per minute and needs to be cleaned for 10 minutes after the production of every 1500 nuts.
hence it can work continuously for 20 min to produce 1500 nuts, then needs 10 min break. So, in 30 min : 1500 Bolts.
Hence, to produce 9000 bolts, time taken = (9000/1500)*30 -10(last cleaning cycle need not be included in production time) = 170 min
To produce the 9000 pairs of nuts and bolts: max of time taken by individual machines to be taken = 170 min
Answer C
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