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Bunuel
A and B take part in a duel. A can strike with an accuracy of 0.6. B can strike with an accuracy of 0.8. A has the first shot, post which they strike alternately. What is the probability that A wins the duel?

A. 11/17
B. 15/23
C. 2/3
D. 7/10
E. 7/9

Solution


    • Let us assume that a denotes probability of A to strike the target and \(a ̅ \) denotes the probability that A doesn’t strike the target.
      o \(a = 0.6\)
      o \(a ̅ = (1-0.6) = 0.4\)
    • Similarly, let us assume that b denotes probability of B to strike the target and \(b ̅ \) denotes the probability that B doesn’t strike the target.
      o \(b = 0.8\)
      o \(b ̅ = (1-0.8) = 0.2\)
    • Now, possible ways in which A can win = A strike the target on his first shot OR A strike the target on his second shot OR A strike the target on his third shot OR .....and so on.
    • Since, A and B are striking alternately.
      o So, the probability of A to win(Let’s say P) \(= a + a ̅*b ̅ *a + a ̅*b ̅ *a ̅*b ̅ *a +a ̅*b ̅ *a ̅*b ̅ *a ̅*b ̅ *a + ……. \)And so on
      o \(P = 0.6 + 0.4*0.2*0.6 + 0.4*0.2*0.4*0.2*0.6 + 0.4*0.2*0.4*0.2*0.4*0.2*0.6 + ………… \)and so on.
      o \(P = 0.6 [1 + (0.08) + (0.08) ^2 + (0.08) ^3 + ……….]\)
    • We can observe that the terms in the bracket [] forms a G.P. with first term as 1 and common ratio as 0.08.
    • Therefore, \(P = 0.6* \frac{1}{1- 0.08} = \frac{0.6}{0.92} = \frac{60}{92} = \frac{15}{23}\)
Thus, the correct answer is Option B.
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Hi Bunuel,

When we say A wins the duel, I think we have to give equal chances to A and B and not set this up disproportionately.
If we are not supposed to give B his second turn, then why even give him the opportunity in the first turn.

IMO the sequences should be (bold parts should be needed)
Game finishes in 1 turn -> A passes * B fails
Game finishes in 2 turns -> [(A passes * B passes) or (A fails * B fails)] * A passes * B fails
Game finishes in 2 turns -> [(A passes * B passes) or (A fails * B fails)] * [(A passes * B passes) or (A fails * B fails)] * A passes * B fails and so on

Hence, we have
A's Win requirement = A passes * B fails = [3/5 * 1/5] = 3/25
All possible reasons for A and B to remain equal at the end of the round = [(A passes * B passes) or (A fails * B fails)] = [2/5*1/5 + 3/5*4/5] = 2/25 + 12/25 = 14/25

Final probability = 3/25 + 14/25 * 3/25 + (14/25)^2 * 3/25 + (14/25)^3 * 3/25 + ......
=> 3/25 [ 1 + (14/25) + (14/25)^2 + (14/25)^3 + .....]
=> 3/25 * 1/[1-(14/25)]
=> 3/25 * 25/11
IMO Probability should be 3/11

I'll await your thoughts.
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Hi Bunuel,

When we say A wins the duel, I think we have to give equal chances to A and B and not set this up disproportionately.
If we are not supposed to give B his second turn, then why even give him the opportunity in the first turn.

IMO the sequences should be (bold parts should be needed)
Game finishes in 1 turn -> A passes * B fails
Game finishes in 2 turns -> [(A passes * B passes) or (A fails * B fails)] * A passes * B fails
Game finishes in 2 turns -> [(A passes * B passes) or (A fails * B fails)] * [(A passes * B passes) or (A fails * B fails)] * A passes * B fails and so on

Hence, we have
A's Win requirement = A passes * B fails = [3/5 * 1/5] = 3/25
All possible reasons for A and B to remain equal at the end of the round = [(A passes * B passes) or (A fails * B fails)] = [2/5*1/5 + 3/5*4/5] = 2/25 + 12/25 = 14/25

Final probability = 3/25 + 14/25 * 3/25 + (14/25)^2 * 3/25 + (14/25)^3 * 3/25 + ......
=> 3/25 [ 1 + (14/25) + (14/25)^2 + (14/25)^3 + .....]
=> 3/25 * 1/[1-(14/25)]
=> 3/25 * 25/11
IMO Probability should be 3/11

I'll await your thoughts.

You’re mixing up alternating turns with simultaneous shots. A and B don’t shoot in the same round. A fires first; if he misses, then B fires. The duel ends as soon as one hits (meaning the hit kills the other).
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I think I took duel in some other sense (like a game) rather than some life and death moment. Thanks.

Bunuel


You’re mixing up alternating turns with simultaneous shots. A and B don’t shoot in the same round. A fires first; if he misses, then B fires. The duel ends as soon as one hits (meaning the hit kills the other).
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