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TheNightKing
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At IIM Bangalore, 60% of the students are boys and the rest are girls. 22 May 2020, 21:14
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D
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55% (hard)

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69% (03:08) correct 31% (03:02) wrong based on 89 sessions

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At IIM Bangalore, 60% of the students are boys and the rest are girls. Further 15% of the boys and 7.5% of the girls are getting a fee waiver. If the number of those getting a fee waiver is 900, find the total number of students getting 50% concession if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?
(a) 3600
(b) 2800
(c) 3200
(d) 3300
(e) None of these
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D
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At IIM Bangalore, 60% of the students are boys and the rest are girls. 23 May 2020, 00:59
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I think it is answer D. This is how I did it.

60% are boys of which 15% are getting a fee waiver - 60% x 15% = 9% of all students
40% are girls of which 7.5% are getting a fee waiver - 40% x 7.5% = 3% of all students

This means that 12% of all students are getting a fee waiver- and that 88% of all students are not getting a fee waiver.
12% = 900 students, and so
88% = 6600 students

Half the people who did not get a fee waiver (6600 students) are eligible to get half fee concession.
6600/2=3300

Let me know if I got it wrong!
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At IIM Bangalore, 60% of the students are boys and the rest are girls. 23 May 2020, 03:53
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TheNightKing
At IIM Bangalore, 60% of the students are boys and the rest are girls. Further 15% of the boys and 7.5% of the girls are getting a fee waiver. If the number of those getting a fee waiver is 900, find the total number of students getting 50% concession if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?
(a) 3600
(b) 2800
(c) 3200
(d) 3300
(e) None of these
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Let number of total students =x

Total Boys = .6x
Total Girls = .4x

Boys getting Waive off = 15% of .6x = .09x
Girls getting waive off = 7.5% of .4x = .03x

.12x=900
x= 7500 - Total number of students

Number of students not getting waiver= 7500-900=6600

50% of not getting waive off =3300

Answer : D
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At IIM Bangalore, 60% of the students are boys and the rest are girls. 22 Sep 2021, 17:06
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Given: At IIM Bangalore, 60% of the students are boys and the rest are girls. Further 15% of the boys and 7.5% of the girls are getting a fee waiver.

Asked: If the number of those getting a fee waiver is 900, find the total number of students getting 50% concession if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?

% of total students (boys) getting a fee waiver = 60%*15% = 9%
% of total students (girls) getting a fee waiver = 40%*7.5% = 3%
% of total students getting a fee waiver = 9% + 3% = 12%
12% of total students = 900
Total students = 900/12% = 7500

50% of those not getting a fee waiver = 50% (7500 - 900) = 50% (6600) = 3300

IMO D
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At IIM Bangalore, 60% of the students are boys and the rest are girls. 23 Sep 2021, 06:09
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Given that 60% are boys, out of which 15% get a fee waiver.
So, % of boys that get a fee waiver would be 15% of 60% which is 9%.
[10% of 60%=6, 5% of 60%=3 and so 15% of 60% would be 6+3=9%]

% of girls is 40%, out of which 7.5% get a fee waiver.
So, % of girls that get a fee waiver would be 7.5% of 40% which is 3%.
[10% of 40=4, 2,5% of 40=1 and so 7.5% would be 3]

Therefore, total % of students that get a fee waiver would be 12%.
12% of the total is 900.
so 4% of the Toal is 300.
Therefore 100% of the total would be 300*25=7500.

No. of students who did not get a few waiver=7500-900=6600.
Therefore, 50% of 6600=3300.

Hope this helps.
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