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03 Jun 2020, 01:55
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
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Question Stats:
58% (02:35) correct
42%
(02:52)
wrong
based on 209
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You are hosting a party and have bought a combination of apple(s), orange(s), and pear(s). Then you slice each apple into 3 pieces, each orange into 4 pieces, and each pear into 5 pieces. Afterwards, you put 2 slices of different kind of fruits on a plate for each guest, and there are no slices left over from this arrangement. If there are 6 fruits in total, what is the least possible number of guests in this party?
A. 10
B. 11
C. 12
D. 13
E. 14
A. 10
B. 11
C. 12
D. 13
E. 14
03 Jun 2020, 06:43
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To determine the least no of people no of slices should be minimum.
and to minimize the number of slices keep the no of apples to maximum... sum of total slices should be in multiple of two.
3 apples 9 pieces
2 oranges 8 slices
1 pear 5 slices
sums up to 22 slices and can be divided into 11 plates hence 11 people.
ans B
and to minimize the number of slices keep the no of apples to maximum... sum of total slices should be in multiple of two.
3 apples 9 pieces
2 oranges 8 slices
1 pear 5 slices
sums up to 22 slices and can be divided into 11 plates hence 11 people.
ans B
03 Jun 2020, 12:28
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nick1816
3A + 4O + 5P has to be even, where A +O +P = 6. A=4, Not possible as it will result in odd value.
9 + 8 + 5 = 22. Possible when A =3, O =2, P =1. So the least number of guests are 11.
B is the answer
