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Bunuel
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Easier way would be to square the numbers

So (10√6)²=600 < 25² -> 10√6 < 25
2√169= 26 > 25
(10√7)²=700 > 25² -> 10√7 > 25

So D

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Squaring 25 we get 625.

Now from options,
I. Squaring \(10\sqrt{6}\) equals to 600 which is < 625

So cancelling options A, C, and E.

II. \(2\sqrt{169 }\) equals to 2 x 13 = 26 which is > 25

III. Squaring \(10\sqrt{7}\) equals to 700 which is > 625.

Thus IMO ans is D, i.e., II and III both.
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25=\(\sqrt{625}\)

I 10\(\sqrt{6}\)=\(\sqrt{600}\) < \(\sqrt{625}\)

II 2\(\sqrt{169}\)=\(\sqrt{676}\) > \(\sqrt{625}\)

III 10\(\sqrt{7}\)=\(\sqrt{700}\) > \(\sqrt{625}\)

Answer D.
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Option I: \(10\sqrt{6} = \sqrt{600} < \sqrt{625} = 25\)

Option II: \(2\sqrt{169} = 2 * 13 = 26 > 25\)

Option III: \(10\sqrt{7} = \sqrt{700} > \sqrt{625} = 25\)

Only Option II and III

Answer D
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