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06 Jul 2020, 08:04
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (02:25) correct
20%
(02:40)
wrong
based on 59
sessions
History
Date
Time
Result
Not Attempted Yet
A man invests Rs. 1,200 at 10% p.a. At the end of the year he withdraws 30% of total amount and pays Rs. 24 as transaction fee from investment. At the end of 2nd year he withdraws 30% of the amount and pays Rs. 93 as transaction fee from investment. What is the balance at the end of the second year?
(A) Rs. 660
(B) Rs. 825
(C) Rs. 600
(D) Rs. 770
(E) Rs. 870
(A) Rs. 660
(B) Rs. 825
(C) Rs. 600
(D) Rs. 770
(E) Rs. 870
06 Jul 2020, 09:43
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Amount at the end of first year after doing all the transaction
=1200×1.1×0.7-24=900
Amount at the end of second year after doing all the transaction
900×1.1×0.7 - 93=600
Option C is the answer
Posted from my mobile device
=1200×1.1×0.7-24=900
Amount at the end of second year after doing all the transaction
900×1.1×0.7 - 93=600
Option C is the answer
Posted from my mobile device
06 Jul 2020, 10:28
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TheNightKing
Break into parts and solve -
Quote:
\(\frac{1200*110}{100}*\frac{70}{100} = 924\)
\(924 - 24 = 900\)
Quote:
\(\frac{900*110}{100}*\frac{70}{100} = 693\)
\(693 - 93 = 600\), Hence Answer must be (C)
