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Bunuel
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Sum of first V integers = V(V+1)/2 = W

Sum of next V integers = V[2*(V+1)+(V-1)1]/2
=> Sum = V[2V + 2 + V - 1]/2
=> Sum = V(2V + V+1)/2
=> Sum = V^2 + W

Ans: D
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i was picking numbers to get D
v=3 numbers 1-2-3 so w=6
v2=3 , numbers 4-5-6 so w2=15
6+3^2=15
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nkme2007
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The sum of the first V positive integers is W. What is the sum of the next V positive integers?

A. VW
B. (V + W)/N
C. V + W
D. W + V^2
E. W - V^2

Let V be 2

Sum of first 2 positive integers = 1+2 = 3 = W

Sum of next 2 positive integers = 3+4 = 7

POE of given options:

A: VW = 6 Wrong
B: (V + W)/N Wrong, as we don't know N
C: V+W = 5 Wrong
D: W + V^2 = 3+2^2 = 7 Fits
E: W - V^2 = 3-2^2 = 7 Wrong

Hence, OA: D

nkme2007 Just curious how did you know that you should try and put in values?
Coz I intially started solving taking variables only. But i liked your approach better.

Posted from my mobile device
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bratbg
nkme2007
Bunuel
The sum of the first V positive integers is W. What is the sum of the next V positive integers?

A. VW
B. (V + W)/N
C. V + W
D. W + V^2
E. W - V^2

Let V be 2

Sum of first 2 positive integers = 1+2 = 3 = W

Sum of next 2 positive integers = 3+4 = 7

POE of given options:

A: VW = 6 Wrong
B: (V + W)/N Wrong, as we don't know N
C: V+W = 5 Wrong
D: W + V^2 = 3+2^2 = 7 Fits
E: W - V^2 = 3-2^2 = 7 Wrong

Hence, OA: D

nkme2007 Just curious how did you know that you should try and put in values?
Coz I intially started solving taking variables only. But i liked your approach better.

Posted from my mobile device

Thanks for liking my approach bratbg. Just try to think if you can substitute any numbers when the question contains variables. This may save a lot of time when the algebraic solution takes time.

All the best.
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out of curiosity, does anyone have an Algebra Approach? I Plugged in Numbers also....


EDIT: Nevermind, I missed a post above. Apologies.
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