yashikaaggarwal
Two persons A and B are standing diametrically opposite on a circular track of with a radius of 3.5 units. They start running in an opposite direction on the circular track and their speeds are four units/min and seven units/min, respectively. On meeting each other, they take rest for half a min and then start running with twice the original speed. In five min, how many times will they take rest together?
A. 6
B. 7
C. 4
D. 5
E. 9
Posted from my mobile deviceGiven:
1. Two persons A and B are standing diametrically opposite on a circular track of with a radius of 3.5 units.
2. They start running in an opposite direction on the circular track and their speeds are four units/min and seven units/min, respectively.
3. On meeting each other, they take rest for half a min and then start running with twice the original speed.
Asked: In five min, how many times will they take rest together?
Their relative speed for the first round = 4 + 7 = 11 units / min
Distance to be covered for first meeting = \(\pi *3.5 = 2* 22/7 * 3.5 = 11\) units since they have to cover half of the circumference.
Distance to be covered in subsequent meetings = 22 units; Since they have to cover full circumference.
For subsequent meetings their relative speed doubles and time taken to cover the distance halves.
Time taken to meet for the first time = 11/11 = 1 mins
Time taken to meet for the second time = 22/22 = 1 mins
Time taken for meetings = {1,1,.5,.25,.125,,,,}
| Meeting number | Travelling time | Rest Time | Total time | Cumulative Time |
| 1 | 1 min | .5 min | 1.5 min | 1.5 min |
| 2 | 1 min | .5 min | 1.5 min | 3 min |
| 3 | .5 min | .5 min | 1 min | 4 min |
| 4 | .25 min | .5 min | .75 min | 4.75 min |
| 5 | .125 min | | | 4.875 min |
Since they meet for 5th time at 4.75 + .125 = 4.875 mins well within 5 mins time
IMO D