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26 Aug 2020, 02:01
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57% (02:14) correct
43%
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based on 53
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A rectangular door measures 5 feet in width by 6 feet, 8 inches in height. What is the distance from one corner of the door to the diagonally opposite corner?
(A) 8 feet, 3 inches
(B) 8 feet, 4 inches
(C) 9 feet
(D) 9 feet, 4 inches
(E) 9 feet, 6 inches
(A) 8 feet, 3 inches
(B) 8 feet, 4 inches
(C) 9 feet
(D) 9 feet, 4 inches
(E) 9 feet, 6 inches
Archit3110
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26 Aug 2020, 02:22
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SajjadAhmad
width ; 5 feet and length 6 + 8/12 feet ; 6.66 feet
so digonal would be√ 25+44.44 ; √69 ; ~ 8.33 feet
i.e 8 feet 4 inches
option B
26 Aug 2020, 06:53
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Diagonal of a rectangle = \(\sqrt{l^2 + b^2}\)
1 foot = 12 inches
Converting into inches, we have width = 5 * 12 = 60 inches and height = (6*12) + 8 = 80 inches
Therefore the diagonal = \(\sqrt{60^2 + 80^2} = \sqrt{3600 + 6400} = \sqrt{10000}\) = 100 inches
Dividing by 12, we get 100 inches = 8 feet 4 inches
Option B
Arun Kumar
1 foot = 12 inches
Converting into inches, we have width = 5 * 12 = 60 inches and height = (6*12) + 8 = 80 inches
Therefore the diagonal = \(\sqrt{60^2 + 80^2} = \sqrt{3600 + 6400} = \sqrt{10000}\) = 100 inches
Dividing by 12, we get 100 inches = 8 feet 4 inches
Option B
Arun Kumar
