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By the rule of arrangements, the number of arrangements of n distinct letters all taken together (no repetition) = n!

Since we are arranging the letters in Alphabetical order:

With A in the first place and with the remaining 4 letters the number of words formed = 1 * 4! = 24


Similarly with E, G, N we can form 24 words each.

Total words formed with A, E, G and N in the 1st place = 24 * 4 = 96.

The 97th word starts with R

RA are in order as per the alphabets

With the remaining 3 alphabets N, G and , the number of words formed = 1 * 1 * 3! = 6


These are RAEGN, RAENG, RAGEN, RAGNE, RANEG, RANGE


Therefore the rank of the word RANGE is 96 + 6 = 102



Option C



in this case, listing of the words was a feasible Option.

But if we had more letters, then a possible method is to keep counting until we have 2 letters remaining.

We know that with R and A as the 1st 2 letters in alphabetical order, we get 1 * 1 * 3! = 6 words

With R, A and E we get 2 words, R, A and G we get 2 words and with R, A and N, we get 2 words

With R, A and N the two words arranged alphabetically would be RANEG and RANGE.

Therefore RANGE is the last of the 6 words and therefore its rank is 96 + 6 = 102


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