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02 Sep 2020, 13:05
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
54% (01:25) correct
46%
(01:22)
wrong
based on 24
sessions
History
Date
Time
Result
Not Attempted Yet
In an election, Party X obtained 8% more votes than Party Y. If only these 2 parties had candidates in the election and no votes were invalid, what percentage of the total votes did Party Y obtain?
A)46%
B)48%
C)54%
D)62%
E)92%
A)46%
B)48%
C)54%
D)62%
E)92%
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02 Sep 2020, 13:17
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Assume ,there were 100 votes in total out of which party had y number of votes
So X would have 108/100of y
As X has 8% more votes
Adding both the votes should give 100
So y +108/100y =100
I.e. y is around 48.
IMO option B should be the answer.
Posted from my mobile device
So X would have 108/100of y
As X has 8% more votes
Adding both the votes should give 100
So y +108/100y =100
I.e. y is around 48.
IMO option B should be the answer.
Posted from my mobile device
03 Sep 2020, 04:29
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Let the number of votes Y got = 100
X gets 8% more than Y = \(100 * \frac{108}{100}\) = 108 votes
Total Votes (Since only these 2 were the only parties and no votes were invalid) = 100 + 108 = 208
% of total votes obtained obtained by Y
\(\frac{Percentage}{100} * Total = Portion\)
\(\frac{Percentage}{100} * 208 = 100\)
% = \(\frac{100 \space * \space 100}{208} = 48.07 \approx 48\)%
Option B
Arun Kumar
X gets 8% more than Y = \(100 * \frac{108}{100}\) = 108 votes
Total Votes (Since only these 2 were the only parties and no votes were invalid) = 100 + 108 = 208
% of total votes obtained obtained by Y
\(\frac{Percentage}{100} * Total = Portion\)
\(\frac{Percentage}{100} * 208 = 100\)
% = \(\frac{100 \space * \space 100}{208} = 48.07 \approx 48\)%
Option B
Arun Kumar
