A budget airline charges each customer e/3 euros for every leg of the

Question

A budget airline charges each customer e/3 euros for every leg of the flights between London and Ibiza. The only exception is that it charges e euros for the first leg of the first round-trip for the same customer. How much is the total cost of n round-trip tickets for one customer?

A. \(\frac{e+ne}{27 }\)

B. \(\frac{2e+2ne}{3 }\)

C. \(\frac{2e+ne}{300}\)

D. \(\frac{2n+ne}{3}\)

E. \(\frac{ne}{9 }\)

A.  \frac{e+ne}{27 } 
 
B.  \frac{2e+2ne}{3 } 
 
C.  \frac{2e+ne}{300} 
 
D.  \frac{2n+ne}{3} 
 
E.  \frac{ne}{9 }

IanStewart · Answer

I assume the question means to say that the cost is "e/3", and not "e I 3".

It's not clear from the question how many "legs" there are on a flight from London to Ibiza. I think the question means to talk about direct flights back and forth between the two places. If someone buys n round-trip tickets, they will then take 2n flights. Except for the first flight, they each cost e/3 euros. So 2n-1 flights cost e/3 euros, and the very first flight costs e euros, and the total cost is

e + (e/3)(2n - 1) = (2e + 2en)/3

TestPrepUnlimited · Answer

Reading the question backwards will help us understand this question (there is debate for whether a round-trip counts as 2 flights but I understand it as 1 flight)
Each customer has "2 legs" for each trip.
The first leg for the very first trip costs  e , and each leg afterwards costs  \frac{e}{3} .
There are n trips, so 2n legs total will be charged, the first leg is charged at  e  and the rest of the (2n - 1) legs are charged at  \frac{e}{3}  each.

Thus the total cost is:  e + (2n - 1)\frac{e}{3} = \frac{2e+2ne}{3} .

Only one answer has the part  \frac{2ne}{3}  and we can use that part solely to determine the answer is B.

Ans: B

stne · Answer

My two cents :
Each round trip consists of two legs ( onward and return )
(So total n round trips have 2n legs )
Now for the first roundtrip there is an onward and return journey .
The onward journey costs  e  (the only exception ) and the return costs  \frac{e}{3}

Remaining  n-1  round trips have  2(n-1)  legs each costing  \frac{e}{3}

Hence total cost is  e + \frac{e}{3}  + 2(n-1) \frac{e}{3} 
Solving the above we get: \frac{2ne +2e}{3}

Hope it's clear.

Ans- B

Rogermoris · Answer

For any round trip, you have 2 journeys(to and fro), hence for n trips, so 2n legs total will be charged
The first leg is charged at e and the rest of the (2n - 1) legs are charged at  \frac{e}{3}   each.

Thus the total cost is:  e+(2n−1)\frac{e}{3}=\frac{(2e+2ne)}{3.}

Hence our answer is option

A budget airline charges each customer e/3 euros for every leg of the

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A budget airline charges each customer e/3 euros for every leg of the

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