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09 Sep 2020, 05:11
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
76% (02:03) correct
24%
(02:14)
wrong
based on 164
sessions
History
Date
Time
Result
Not Attempted Yet
There are twice as many boys as girls in the class. If 20% of the boys and 35% of the girls have already handed over their result cards, what percent of the students have not yet handed over their cards?
(A) 15
(B) 25
(C) 35
(D) 55
(E) 75
(A) 15
(B) 25
(C) 35
(D) 55
(E) 75
yashikaaggarwal
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09 Sep 2020, 05:32
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There are twice as many boys as girls in the class. => B = 2G
let class have 90 students,
60 Boys and 30 girls.
If 20% of the boys and 35% of the girls have already handed over their result cards.
the students who have not submitted their report cards =
60*(100-20)/100 + 30*(100-35)/100
60*80/100 + 30*65/100
48+ 19.5
67.5
the percentage who didn't hand over the report card = 67.5/90*100 = 75
Answer is E
let class have 90 students,
60 Boys and 30 girls.
If 20% of the boys and 35% of the girls have already handed over their result cards.
the students who have not submitted their report cards =
60*(100-20)/100 + 30*(100-35)/100
60*80/100 + 30*65/100
48+ 19.5
67.5
the percentage who didn't hand over the report card = 67.5/90*100 = 75
Answer is E
09 Sep 2020, 09:48
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SajjadAhmad
Strange question, because of the answer choices - of course you can use weighted average principles to solve precisely. If we have twice as many boys as girls, the overall average will be 'twice as close' to the boys' average (which is 20%, while the girls' average is 35%), so 25% of the class will have handed over their cards, and 75% will thus have not.
But we don't even need to do that. 80% of boys have not handed over cards, and 65% of girls have not. So the percentage of students overall who have not handed over cards must be somewhere between 65% and 80%, and only one answer choice makes any sense.
