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24 Sep 2020, 06:51
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C
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Difficulty:
5%
(low)
Question Stats:
90% (01:20) correct
10%
(01:12)
wrong
based on 97
sessions
History
Date
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To feed 10 bears for one week at the zoo requires 560 fish. If each bear eats the same amount of fish, how many fish are required to feed two fewer bears for two weeks?
A. 448
B. 864
C. 896
D. 920
E. 1020
A. 448
B. 864
C. 896
D. 920
E. 1020
24 Sep 2020, 08:52
Kudos
Bookmarks
Method 1:
10 Bears eat 560 fish in 7 days
10 Bears eat 80 Fish / day
Therefore 1 Bear eats 8 fish /Day
Now we have 8 bears, who will eat 64 fish/day
Therefore in 14 days, the fish required = 14 * 64 = 896 fish
Method 2: We can also use the concept of Man Days here, which is \(\frac{M_1* T_1}{W_1}= \frac{M_1 * T_1}{W_1}\)
Let the Total Fish required = x
Therefore \(\frac{10 * 7}{560}= \frac{8 * 14}{x}\)
x = 896
Option C
Arun Kumar
10 Bears eat 560 fish in 7 days
10 Bears eat 80 Fish / day
Therefore 1 Bear eats 8 fish /Day
Now we have 8 bears, who will eat 64 fish/day
Therefore in 14 days, the fish required = 14 * 64 = 896 fish
Method 2: We can also use the concept of Man Days here, which is \(\frac{M_1* T_1}{W_1}= \frac{M_1 * T_1}{W_1}\)
Let the Total Fish required = x
Therefore \(\frac{10 * 7}{560}= \frac{8 * 14}{x}\)
x = 896
Option C
Arun Kumar
24 Sep 2020, 10:06
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Sajjad1994
The given rate is 560 fish per week for 10 bears. Thus if we account for each bear, the rate is 56 fish per week per bear.
The question now asks for how many fish under 8 bears and 2 weeks, which is 56 * 8 * 2 = 112*8 = 800 + 96 = 896.
Ans: C
