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01 Oct 2020, 04:45
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (01:04) correct
18%
(00:41)
wrong
based on 80
sessions
History
Date
Time
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Not Attempted Yet
In an xy-coordinate system, which point lies in the interior of a circle with center (0,0) and radius 3?
A. (1, −3)
B. (−1, −2)
C. (−3,1)
D. (0,3)
E. (3,3)
A. (1, −3)
B. (−1, −2)
C. (−3,1)
D. (0,3)
E. (3,3)
01 Oct 2020, 05:01
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For the point to lie inside the circle.
It should satisfy the equation x^2+y^2<r^2 (r^2 =9 here )
Only B satisfies the above equation. So answer is B , IMO
Posted from my mobile device
It should satisfy the equation x^2+y^2<r^2 (r^2 =9 here )
Only B satisfies the above equation. So answer is B , IMO
Posted from my mobile device
01 Oct 2020, 05:05
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A. (1, −3) => Distance from center = \(\sqrt{1^{2} + (-3)^2}\) = \(\sqrt{10}\) > 3 so outside
B. (−1, −2) => Distance from center = \(\sqrt{(-1)^{2} + (-2)^2}\) = \(\sqrt{5}\) < 3 so inside
C. (−3,1) => Distance from center = \(\sqrt{(-3)^{2} + (1)^2}\) = \(\sqrt{10}\) > 3 so outside
D. (0,3) => Distance from center = \(\sqrt{(0)^{2} + (3)^2}\) = \(\sqrt{9}\) = 3 so on the edge
E. (3,3) => Distance from center = \(\sqrt{(3)^{2} + (3)^2}\) = \(\sqrt{18}\) > 3 so outside
Ans B IMO.
B. (−1, −2) => Distance from center = \(\sqrt{(-1)^{2} + (-2)^2}\) = \(\sqrt{5}\) < 3 so inside
C. (−3,1) => Distance from center = \(\sqrt{(-3)^{2} + (1)^2}\) = \(\sqrt{10}\) > 3 so outside
D. (0,3) => Distance from center = \(\sqrt{(0)^{2} + (3)^2}\) = \(\sqrt{9}\) = 3 so on the edge
E. (3,3) => Distance from center = \(\sqrt{(3)^{2} + (3)^2}\) = \(\sqrt{18}\) > 3 so outside
Ans B IMO.
