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6 workers take 2 hours to finish the work.

Therefore the time taken by 1 worker = 12 hours

The new worker works at 4/5 capacity of the initial workers.

Therefore the time taken by 1 worker (new) = (5/4) * 12 = 15hours

Amount of work done by 1 worker in 1 hour = 1/15

Therefore the work done by 9 workers in 1 hour = 9/15 = 3/5

Therefore the time taken (flipping the numerator and denominator = 5/3


Option D

Arun Kumar



hello, i still couldn't understand the problem. why are we multiplying time taken by 5/4 and not 4/5. can you please elaborate?


when you work at 4/5 th capacity you will take more time than normal.

This can be explained in terms of efficiency. The more efficient you are, the lesser time you take. So efficiency is inversely proportional to time.


Now E (New) = 4/5 (E (old)

So E (New) / E(old) = 4/5

Therefore Time (New) / Time (old) = 5/4

Time (new) = 5/4 Time (old) = 5/4 * 12 = 15

Hope this helps

Arun Kumar
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atsdabhay
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6 workers take 2 hours to finish the work.

Therefore the time taken by 1 worker = 12 hours

The new worker works at 4/5 capacity of the initial workers.

Therefore the time taken by 1 worker (new) = (5/4) * 12 = 15hours

Amount of work done by 1 worker in 1 hour = 1/15

Therefore the work done by 9 workers in 1 hour = 9/15 = 3/5

Therefore the time taken (flipping the numerator and denominator = 5/3


Option D

Arun Kumar



hello, i still couldn't understand the problem. why are we multiplying time taken by 5/4 and not 4/5. can you please elaborate?


when you work at 4/5 th capacity you will take more time than normal.

This can be explained in terms of efficiency. The more efficient you are, the lesser time you take. So efficiency is inversely proportional to time.


Now E (New) = 4/5 (E (old)

So E (New) / E(old) = 4/5

Therefore Time (New) / Time (old) = 5/4

Time (new) = 5/4 Time (old) = 5/4 * 12 = 15

Hope this helps

Arun Kumar


is it similar to the concept saying if 5 units of work is done in 4 hours then time taken to complete 5 work = 4/5 hours?
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6 men can finish a piece of work in 2 hours. How long will 9 men take to finish the work if they can work only at 4/5th the capacity of the initial workers?

A. 5/12
B. 16/15
C. 3/2
D. 5/3
E. 2
\(\frac{6*2}{9}*\frac{5}{4}=\frac{5}{3}\), Answer must be (D)
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\(\frac{(M_1 * H_1)}{ W_1} = \frac{(M_2 * H_2)}{ W_2}\)

=> \(\frac{(6 * 2) }{ 1} = \frac{9 * H_2}{\frac{5}{4}}\)

=> 5 * 6 * 2 = 4 * 9 * \(H_2\)

=> \(H_2\) = \(\frac{5}{3}\)

Answer D
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amount = rate * time.
Rate and time are inversely related. If John can complete a job in \(\frac{4}{5}\) hours, his rate is \(\frac{5}{4}\).

6 men can finish a piece of work in 2 hours. 1 man can finish a piece of work in 12 hours.

How long will 9 men take to finish the work if they can work only at 4/5th the capacity of the initial workers?

9 men rate = \(\frac{12 hours }{ 9 men}\)

\(\frac{12}{9}\)*\(\frac{5}{4}\) =\(\frac{5}{3}\)

Answer is D.
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Total manhours = 6 x 2 = 12
New workers capacity = \(\frac{4}{5}\)

New manhours = 12 x \(\frac{5}{4}\)

Total time required = 12 x \(\frac{5}{4}\) x \(\frac{1}{9}\)

= \(\frac{5}{3}\)

Ans D
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