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Can anyone explain why we took E as 5. I am not able to understand it.
ABCDE × A = EEEEEE
In the correctly worked multiplication problem shown above, A, B, C, D, and E are different digits, what is value of A + B + C + D + E ?

A. 26
B. 27
C. 28
D. 29
E. 30
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Can anyone explain why we took E as 5. I am not able to understand it.
ABCDE × A = EEEEEE
In the correctly worked multiplication problem shown above, A, B, C, D, and E are different digits, what is value of A + B + C + D + E ?

A. 26
B. 27
C. 28
D. 29
E. 30
Since ABCDE = 15873 x E

For what value of E, will you get E x 3 as E?
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ABCDE × A = EEEEEE
In the correctly worked multiplication problem shown above, A, B, C, D, and E are different digits, what is value of A + B + C + D + E ?

A = 1 is not feasible since ABCDE = EEEEE; But the digits are different

E = 1; ABCD1*A = 111111; Not feasible
E = 2; ABCD2*A = 222222; A=6; 6BCD2*6=222222; 6BCD2 = 37037; All digits are different; Not feasible
E = 3; ABCD3*A = 333333; Not feasible
E = 4; ABCD4*A = 444444; A=6; 6BCD4*6 = 666666; 6BCD4=111111; Not feasible

E = 5; ABCD5*A = 555555; A=3; 3BCD5*3 = 555555; 3BCD5 = 555555/3; Not feasible
A = 5; 5BCD5*5 = 555555; 5BCD5 = 111111; Not feasible
A = 7; 7BCD5*7 = 555555; 7BCD5 = 555555/7=79365; Feasible since all digits are different

79365*7 = 555555
A+B+C+D+E = 7+9+3+6+5 = 30

IMO E
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