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13 Oct 2020, 07:30
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B
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Difficulty:
35%
(medium)
Question Stats:
75% (02:37) correct
25%
(03:13)
wrong
based on 66
sessions
History
Date
Time
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Not Attempted Yet
In the figure above, QR is parallel to ST. What is the measure of angle x?
A. 35
B. 45
C. 65
D. 70
E. 110
Attachment:
1.jpg [ 13.92 KiB | Viewed 4313 times ]
13 Oct 2020, 08:58
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Let the point of intersection of QR be U on line PS and V on line PT
Sum of the exterior angles of a polygon = 360
In triangle PUV, y + 115 + y + 25 = 360
2y = 360 - 140 = 220
y = 110
Since QR is \\ to ST, \(\angle{PVU}\) will be equal to x as they are corresponding angles.
\(\angle{PVU}\) = 180 - (y + 25), as they lie on the same line
Therefore x = 180 - (y + 25) = 180 - (110 + 25) = 180 - 135 = 45
Option B
Arun Kumar
Sum of the exterior angles of a polygon = 360
In triangle PUV, y + 115 + y + 25 = 360
2y = 360 - 140 = 220
y = 110
Since QR is \\ to ST, \(\angle{PVU}\) will be equal to x as they are corresponding angles.
\(\angle{PVU}\) = 180 - (y + 25), as they lie on the same line
Therefore x = 180 - (y + 25) = 180 - (110 + 25) = 180 - 135 = 45
Option B
Arun Kumar
13 Oct 2020, 20:30
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In the figure above, QR is parallel to ST. What is the measure of angle x?
A. 35
B. 45
C. 65
D. 70
E. 110
Explanation:
Applying external angle theorem in triangle PQR,
y=(180-115)+(180-y-25)
y=180+40-y
y=110
now QR is parallel to ST
so, angle PRQ=x
x=180-(y+25)
x=180-110-25
x=45
Hence B is the correct answer.
A. 35
B. 45
C. 65
D. 70
E. 110
Explanation:
Applying external angle theorem in triangle PQR,
y=(180-115)+(180-y-25)
y=180+40-y
y=110
now QR is parallel to ST
so, angle PRQ=x
x=180-(y+25)
x=180-110-25
x=45
Hence B is the correct answer.
