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Probability(male U above 16) = P(A)+P(B)-P(AnB)= 500/900+180/900-100/900
= 50/90+18/90-10/90
= 58/90
= 29/45
Option D

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Total males: 500 [100 > 16 and 400 are less than equal to 16 years]

Total females: 400 [80 > 16 and 320 are less than equal to 16 years]

Total: 500 + 400 = 900

Probability(a male or is above 16 years of age): P(Male) + P( above 16 years) - P(Both)

=> \(\frac{500 }{ 900} + \frac{180 }{ 900} - \frac{100 }{ 900}\)

=> \(\frac{5}{9} + \frac{1}{5} - \frac{1}{9}\)

=> \(\frac{29}{45}\)

Answer D
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Bunuel
In a certain college, 100 out of 500 males are above 16 years old and 80 out of 400 females are above 16 years of age. What is the probability that a student selected for a particular grant is a male or is above 16 years of age?

A. 13/45

B. 1/3

C. 7/15

D. 29/45

E. 7/9
Solution:

The total number of students is 500 + 400 = 900. The number of students who are male or above 16 years of age is:

#(Male) + #(Above 16 years of age) - #(Male and above 16 years of age)

= 500 + (100 + 80) - 100

= 580

Therefore, the probability that a student selected for a particular grant is a male or is above 16 years of age is 580/900 = 29/45.

Answer: D
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