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17 Oct 2020, 08:45
Kudos
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
77% (00:41) correct
23%
(00:39)
wrong
based on 62
sessions
History
Date
Time
Result
Not Attempted Yet
The area of circle O is 64π. The perimeter of square ABCD is
(A) 16
(B) 32
(C) 64
(D) 32π
(E) 64π
Attachment:
2020-10-17_19-29-54.png [ 52.36 KiB | Viewed 2643 times ]
17 Oct 2020, 09:27
Kudos
Bookmarks
pi*r^2 = 64*pi
=> r = 8
=> 2r = 16
=> perimeter = 4*16 = 64 (c)
=> r = 8
=> 2r = 16
=> perimeter = 4*16 = 64 (c)
28 Dec 2021, 05:38
Kudos
Bookmarks
Given, the area of circle O is 64π
=> π * r * r =64 π where r is the radius of the circle
=> r = 8 and diameter =2r = 2*8 =16
The diameter of the circle is the side of the square.
If the side of the square is a, then a = 16
Perimeter = 4 * side
= 4 * 16 = 64 unit square
(option c)
D.S
GMAT SME
=> π * r * r =64 π where r is the radius of the circle
=> r = 8 and diameter =2r = 2*8 =16
The diameter of the circle is the side of the square.
If the side of the square is a, then a = 16
Perimeter = 4 * side
= 4 * 16 = 64 unit square
(option c)
D.S
GMAT SME
