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22 Oct 2020, 12:36
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72% (02:43) correct
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Simple interest on a certain sum for 3 years at 8% per annum is equal to half the compound interest on $4000 for 2 years at 10% per annum. What is the sum placed on simple interest?
A. $840
B. $1250
C. $1550
D. $1750
E. $1950
A. $840
B. $1250
C. $1550
D. $1750
E. $1950
22 Oct 2020, 15:58
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Compound interest on $4000 for 2 years=400+440=840
SI = 420
\(\frac{Sum*3*8}{100} = 420\)
Sum = $1750
SI = 420
\(\frac{Sum*3*8}{100} = 420\)
Sum = $1750
Bunuel
22 Oct 2020, 17:05
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Data:
Simple Interest
T = 3 years
R = 8 %
P = ?
Compound Interest
P = 4,000 $
T = 2 years
R = 10%
(P x 8 x 3) / 100 = [[4000 ( 1+0.1)´2 - 4000]-4000]/2
P= 1750
Simple Interest
T = 3 years
R = 8 %
P = ?
Compound Interest
P = 4,000 $
T = 2 years
R = 10%
(P x 8 x 3) / 100 = [[4000 ( 1+0.1)´2 - 4000]-4000]/2
P= 1750
