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Commonly used triplets in the GMAT = 3-4-5.

Answer C
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at AC is longest side or say diameter and ∆ABC is right angled at B which makes it 30:60:90 and 3:4:5 sided ∆
BC is 4
option C


Sajjad1994
Attachment:
manhattan.jpg

Triangle ABC is inscribed in the circle and line segment AC passes through the center of the circle. If the length of line segment AB is 3 and the length of line segment AC is 5, then what is the length of line segment BC ?

(A) 2

(B) 3

(C) 4

(D) 6

(E) 8
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Sajjad1994
Attachment:
manhattan.jpg

Triangle ABC is inscribed in the circle and line segment AC passes through the center of the circle. If the length of line segment AB is 3 and the length of line segment AC is 5, then what is the length of line segment BC ?

(A) 2

(B) 3

(C) 4

(D) 6

(E) 8


Solution:

When the hypotenuse of an inscribed triangle is also the diameter of the circle, the triangle is a right triangle.

We are given that one leg (AB) of the right triangle is 3 and the hypotenuse (AC) is 5. Thus, using our knowledge of Pythagorean triples, we are assured that this is a 3-4-5 triangle, and so line segment BC = 4.

Answer: C
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Abhishek009
Sajjad1994
Attachment:
manhattan.jpg

Triangle ABC is inscribed in the circle and line segment AC passes through the center of the circle. If the length of line segment AB is 3 and the length of line segment AC is 5, then what is the length of line segment BC ?

(A) 2

(B) 3

(C) 4

(D) 6

(E) 8
3 - 4 - 5 Triangle, hence, BC = 4 , Answer must be (C)


What is a 3-4-5 triangle? And how do I know that it is a 3-4-5 triangle?
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