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CrackverbalGMAT, can you please clarify why you multiplied by 3 when you calculated probability of getting 2 tails and 1 head?
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When we toss a fair two-sided coin then we have equal probability of getting head/tail in each toss
So. P(T) = P(H) = 0.5

Now, we are tossing the coin three times so we will get a total of \(2^3 \)= 8 cases.
Refer below image to understand the 8 cases

Attachment:
Image.jpg
Image.jpg [ 32.26 KiB | Viewed 3591 times ]

We ween to find the probability that we get at least 2 heads, i.e. 2 or more heads
So, there are four cases (highlighted in the image) where we will have 2 or more heads

=> P(At least 2 heads) = \(\frac{4}{8}\) = \(\frac{1}{2}\)

So, Answer will be D
Hope it helps!

Watch the following video to learn How to Solve Probability with Coin Toss Problems

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