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IMO-C

Volume of rectangular solid = 5*5*12 = 300

Volume of Cylindrical container = π*r^2*h = 9πh

Volume of rectangular solid = 4 * Volume of Cylindrical container
300 = 4 * 9πh
75 = 9πh
h = 25/3π
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Bunuel
A container in the shape of a rectangular solid with dimensions 5, 5, and 12 has four times the volume of a cylindrical container with radius 3. What is the height of the cylinder?


A. \(\frac{25}{\pi}\)

B. \(\frac{25}{2\pi}\)

C. \(\frac{25}{3\pi}\)

D. \(\frac{25}{4\pi}\)

E. \(5\pi\)


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\(5*5*12 = 4*π3^2*h\)

Or, \(5*5*4= 4*π3*h\)

So, \(25 = 3πh\)

Or, \(h = \frac{25}{3π}\), Answer is (C)
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Volume of solid = 5x5x12 = 300

Volume of cylindrical container = π*3^2*h = 9πh

Now, 300 = 4 x 9πh
75 = 9πh
h = 25/3π

Option C

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ANSWER IMO C

Vol (rectangular solid) = 5*5*12
Vol (Cylindrical container) = π*r^2*h

=> 300 = 4 * 9πh
75 = 9πh
h = 25/3π


Bunuel
A container in the shape of a rectangular solid with dimensions 5, 5, and 12 has four times the volume of a cylindrical container with radius 3. What is the height of the cylinder?


A. \(\frac{25}{\pi}\)

B. \(\frac{25}{2\pi}\)

C. \(\frac{25}{3\pi}\)

D. \(\frac{25}{4\pi}\)

E. \(5\pi\)


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