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02 Dec 2020, 12:45
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C
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Difficulty:
45%
(medium)
Question Stats:
73% (02:36) correct
27%
(02:50)
wrong
based on 135
sessions
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Ramesh has two examinations on Wednesday - Engineering mathematics in the morning and Engineering Drawing in the afternoon. He has a fixed amount of time to read the textbooks of both these subjects on Tuesday. During this time he can read 80 pages of Engineering Mathematics and 100 pages of Engineering drawing. Alternatively, he can also read 50 pages of Engineering Mathematics and 250 pages of Engineering drawing. Assume that the amount of time it takes to read one page of the textbook of either subject is constant. Ramesh is confident about Engineering Drawing and wants to devote full time to reading Engineering Mathematics. The number of Engineering Mathematics text book pages he can read on Tuesday is :
A. 500
B. 300
C. 100
D. 60
E. 50
A. 500
B. 300
C. 100
D. 60
E. 50
12 Dec 2020, 06:07
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Bunuel
Let the total time taken to read = t
80M + 100D = t ... (1) and
50M + 250D = t ... (2)
Time taken to read 80 math pages and 100 drawing pages = time taken to read 50 math pages and 250 drawing pages.
80M + 100D = 50M + 250D
30M = 150D
Or D = \(\frac{30}{150} = \frac{1}{5}\) M
Substituting in equation (1), 80M + 100 * \(\frac{1}{5}\) M = 80M + 20M = 100M
So he can read 100 math pages in the given period of time.
Option C
Arun Kumar
14 May 2023, 01:26
Kudos
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