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03 Dec 2020, 08:00
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
78% (02:31) correct
22%
(02:35)
wrong
based on 60
sessions
History
Date
Time
Result
Not Attempted Yet
21 pencils and 29 pens cost $79. But if the number of pencils and pens were interchanged, the cost would have reduced by $8. What is the cost of each pen?
A. $1
B. $2
C. $3
D. $4
E. $5
A. $1
B. $2
C. $3
D. $4
E. $5
yashikaaggarwal
Senior Moderator - Masters Forum
Joined: 19 Jan 2020
Last visit: 29 Mar 2026
Posts: 3,089
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03 Dec 2020, 12:45
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Let the pencil cost be X
and the pen cost be Y
so,
21X + 29Y = 79
whereas, 21Y + 29X = 71 (by interchanging costs of pen and pencils)
(21X+29Y = 79) x 29
(29X+21Y = 71) x 21
--------------------------
609X + 841Y = 2291
609X + 441Y = 1491
-------------------
400Y = 800
Y = 2
Answer is B
and the pen cost be Y
so,
21X + 29Y = 79
whereas, 21Y + 29X = 71 (by interchanging costs of pen and pencils)
(21X+29Y = 79) x 29
(29X+21Y = 71) x 21
--------------------------
609X + 841Y = 2291
609X + 441Y = 1491
-------------------
400Y = 800
Y = 2
Answer is B
03 Dec 2020, 13:35
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Bookmarks
The change in the total cost is due to the extra number of pens
I.e. (number of pens - number of pencils =8)
8y-8x= 8
Y is price of pen before swapping. X is price of pencil before swapping.
So y-x=1
Substituting value of x as 1 and y as 2, we get 21x+ 29y= 79
So y is 2 , answer is B, IMO
Posted from my mobile device
I.e. (number of pens - number of pencils =8)
8y-8x= 8
Y is price of pen before swapping. X is price of pencil before swapping.
So y-x=1
Substituting value of x as 1 and y as 2, we get 21x+ 29y= 79
So y is 2 , answer is B, IMO
Posted from my mobile device
