Bunuel
How many different triangles exist in which no two sides are of the same length, each side is of integral unit length and the perimeter of the triangle is less than 14 units?
A. 3
B. 4
C. 5
D. 6
E. 7
Let the sides be a, b, c
Thus: a + b + c < 14;
None of a, b, c are equal to each other
Also, sum of the lengths of any 2 sides must exceed the length of the 3rd side; i.e. max length of a side must be less than half the perimeter
Case 1: a + b + c = 13 =>
# max length = 6: other 2 sides = 3, 4 or 2, 5 --->
2 triangles# max length = 5: other 2 sides = 4, 4 (not allowed) or 3, 5 (also not allowed)
# max length cannot be 4 or less since it is less than the mean 13/3 = 4.33
Case 2: a + b + c = 12 =>
# max length = 5: other 2 sides = 3, 4 --->
1 triangle# max length cannot be 4 or less since 4 is the mean 12/3 = 4
Case 3: a + b + c = 11 =>
# max length = 5: other 2 sides = 2, 4 --->
1 triangle# max length = 4: other 2 sides = 3, 4 (not allowed)
# max length cannot be 3 or less since it is less than the mean 11/3 = 3.67
Case 4: a + b + c = 10 =>
# max length = 4: other 2 sides = 3, 3 (not allowed) or 2, 4 (also not allowed)
# max length cannot be 3 or less since it is less than the mean 10/3 = 3.33
Case 5: a + b + c = 9 =>
# max length = 4: other 2 sides = 3, 2 --->
1 triangle# max length cannot be 3 or less since it is less than the mean 9/3 = 3
Case 6: a + b + c = 8 or lower =>
The minimum sum of 3 unequal numbers that can form a triangle = 2 + 3 + 4 = 9
(Think why 1 + 2 + 3 = 6 does not work)
Thus, none of these cases would work
Total triangles = 2 + 1 + 1 + 1 = 5
Answer C