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This is a weighted average question:

Let the quantity of wheat i.e 3.2 per kg = x
Let the quantity of wheat i.e 2.9 per kg = y

\(\frac{3.2x + 2.9y}{x+y} = 3.08\)

\(3.2x + 2.9y = 3.08x + 3.08y\)

\(0.12x = 0.18y\)

\(\frac{x}{y} = \frac{18}{12} = \frac{3}{2}\) (C)
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Shouldn't the lower quantity be on the left side?

Kindly explain what i'm missing here!
Abhishek009
Bunuel
In what ratio must wheat at $3.20 per kg be mixed with wheat at $2.90 per kg so that the mixture be worth $3.08 per kg?

A. 3 : 4

B. 2 : 3

C. 3 : 2

D. 4 : 3

E. 5 : 3
3.20__________________________________2.90
_________________3.08_________________
0.18__________________________________0.12

Or, \(18 : 12 = > 3 : 2\), Answer must be (C)
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srikanth9989
Shouldn't the lower quantity be on the left side?

Kindly explain what i'm missing here!
Abhishek009
Bunuel
In what ratio must wheat at $3.20 per kg be mixed with wheat at $2.90 per kg so that the mixture be worth $3.08 per kg?

A. 3 : 4

B. 2 : 3

C. 3 : 2

D. 4 : 3

E. 5 : 3
3.20__________________________________2.90
_________________3.08_________________
0.18 (|2.9-3.08|)__________________________________0.12 (|3.2 - 3.08|)

Or, \(18 : 12 = > 3 : 2\), Answer must be (C)
If it's the bottom two numbers you are talking about, then it's a method called alligation in which you cross-subtract with middle value (as highlighted).

If it's the top two numbers you are talking about, then it actually does not matter since even if you end up with 2:3 post cross subtraction, your final answer will be 3:2 since you are asked ratio of higher priced wheat to lower priced wheat.
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