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11 Dec 2020, 06:00
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
27% (01:56) correct
73%
(01:41)
wrong
based on 22
sessions
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Which of the following best describes the relationship between the graph of \(y = \frac{2}{x^2}\) and the graph of \(x = \frac{2}{y^2}\) in the xy-plane?
(A) Mirror images symmetrical about the x-axis
(B) Mirror images symmetrical about the y-axis
(C) Mirror images symmetrical about the line of the equation x = y
(D) Mirror images symmetrical about the line of the equation x = –y
(E) The second graph will coincide with the first one, if the second one is rotated 90 degrees counterclockwise around the origin
(A) Mirror images symmetrical about the x-axis
(B) Mirror images symmetrical about the y-axis
(C) Mirror images symmetrical about the line of the equation x = y
(D) Mirror images symmetrical about the line of the equation x = –y
(E) The second graph will coincide with the first one, if the second one is rotated 90 degrees counterclockwise around the origin
callmeDP
Joined: 25 Oct 2020
Last visit: 12 Dec 2022
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Location: India
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11 Dec 2020, 06:15
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IMO E
A pretty straight forward question, if you know what squaring a variable does to the other variable:
y = x^2 => This means that y can never be negative because, for all real values of X, you will always have Y Positive.
y = \(\frac{2}{x^2}\) => This means Y can never be NEGATIVE or the graph is above x - axis and symmetrical about positive Y - axis
x = \( \frac{2}{y^2}\) => This means X can never be NEGATIVE or the graph is right of y - axis and symmetrical about positive X - axis
And if reverse deduce the options to image a point of similarity between these two then you will get,
E
A pretty straight forward question, if you know what squaring a variable does to the other variable:
y = x^2 => This means that y can never be negative because, for all real values of X, you will always have Y Positive.
y = \(\frac{2}{x^2}\) => This means Y can never be NEGATIVE or the graph is above x - axis and symmetrical about positive Y - axis
x = \( \frac{2}{y^2}\) => This means X can never be NEGATIVE or the graph is right of y - axis and symmetrical about positive X - axis
And if reverse deduce the options to image a point of similarity between these two then you will get,
E
14 Dec 2020, 13:37
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Hi DP, can u please explain with diagram ? i am not able to understand how you selection option E ?
