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11 Dec 2020, 06:30
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
81% (01:34) correct
19%
(01:57)
wrong
based on 36
sessions
History
Date
Time
Result
Not Attempted Yet
A certain type of cancer cell divides into two cells every four seconds. How many cells are observable 32 seconds after observing a total of four cells?
(A) 1,024
(B) 2,048
(C) 4,096
(D) 5,512
(E) 8,192
(A) 1,024
(B) 2,048
(C) 4,096
(D) 5,512
(E) 8,192
callmeDP
Joined: 25 Oct 2020
Last visit: 12 Dec 2022
Posts: 70
Given Kudos: 274
Status:No one but you matter
Location: India
Schools: Alberta '23 HEC Montreal
11 Dec 2020, 06:41
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A very simple question again, let's solve this with a cheeky approach
If something doubles in T years, then it will become four times in 2T years, also it will become 8 times in 3T years
In general, It becomes 2(power "n") times in {n}T years.
Here,
Doubles every 4 seconds ( assumes T = 4 ) ; Therefore 32 seconds = {8}T or n = 8
Thus it becomes {2 ( power "8")} times the initial value, which is {2 ( power "8")} * 4 = 1024
IMO A
If something doubles in T years, then it will become four times in 2T years, also it will become 8 times in 3T years
In general, It becomes 2(power "n") times in {n}T years.
Here,
Doubles every 4 seconds ( assumes T = 4 ) ; Therefore 32 seconds = {8}T or n = 8
Thus it becomes {2 ( power "8")} times the initial value, which is {2 ( power "8")} * 4 = 1024
IMO A
11 Dec 2020, 23:56
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The correct answer is \(A\). Solve for \(T\) in the general equation \( a.r^(n-1) = T \). Let \( a = 4, r = 2, \) and \(n = 9 \).
\(4*2^(9-1) = T \)
\( T = 1024 \)
\(4*2^(9-1) = T \)
\( T = 1024 \)
