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Vallabhm001
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Given:
1. A bought an article for $M and sold it for $N and he gets profit of 42\(\frac{6}{7}\)%.
2. Had he bought for $50 more than M and sold it for $75 more than N, he would have made profit of 43\(\frac{3}{4}\)%.
Asked: What is the value of M?

(N - M) / M = 42 6/7%
N - M = 42 6/7% M
N = 142 6/7 % M

(N +75 - M - 50) / (M+50) = (N-M+25)/(M+50) = 43 3/4 %

N- M +25 = 43 3/4% (M+50) = 43 3/4%M + 21 7/8
N = M - 25 + 43 3/4%M + 21 7/8 = 143 3/4% M - 3 1/8
142 6/7 %M = 143 3/4%M - 3 1/8
1 (3/4-6/7) %M = 25/8
(7/4-6/7)%M = 25/8
(49-24)/28 % M = 25/8
(25/2800) M = 25/8
M = 2800/8 = $350

IMO E
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Vallabhm001
I was looking for some easy ways to solve this type of questions, but I'm not getting right answers.

M = M + 42.85 ----------------(1)
M+50 = (M + 42.85) + 75 + 43.75---------------(2)


Friend, you have written wrong equation, check my post for the correct equation.

Breaking it down further for your ease, Let me know if it helps.

A bought an article for $M and sold it for $N and he gets profit of 42\(\frac{6}{7}\)%.

Eqn: M ( 1 + 0.428 ) = N ......... (1)

Cost price(CP here "M") ; Selling price (SP here "N") ; profit percentage ( here 42\(\frac{6}{7}\)% but for simplicity let's assume "X")

Profit percentage (X) = \(\frac{ SP - CP}{ CP }\) * 100

OR \(\frac{ X}{100}\) * CP = SP - CP

OR CP + [ \(\frac{ X}{100}\) * CP ] = SP

OR CP [ 1 + \(\frac{ X}{100}\) ] = SP

OR here, M [ 1 + 42\(\frac{6}{7}\) /100 ] = N

42\(\frac{6}{7}\) /100 = 0.428

so, M ( 1 + 0.428 ) = N

Same way try making other equation following the above steps.
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Vallabhm001
A bought an article for $M and sold it for $N and he gets profit of 42\(\frac{6}{7}\)%. Had he bought for $50 more than M and sold it for $75 more than N, he would have made profit of 43\(\frac{3}{4}\)%. What is the value of M?

A. $250
B. $475
C. $300
D. $500
E. $350

We can PLUG IN THE ANSWERS, which represent the value of M.

Case 1: A dealer bought an article for $M, sold it for $N, and made a profit of 42\(\frac{6}{7}\)%.
Since the fraction here has a denominator of 7, the correct answer is almost certain to be a multiple of 7.
Case 2: Had he bought the article for $50 more than M and sold it for $75 more than N, he would have made a profit of 43\(\frac{3}{4}\)%.
Since the fraction here has a denominator of 4, the value of M+50 -- in other words, 50 more than the correct answer -- is almost certain to be a multiple of 4.

Only E -- which implies that M=350 and that M+50=400 -- satisfies both conditions.
When the correct answer is plugged in, Case 2 must yield a profit of 43.75%.

E: 350
Case 1:
M = 350
N = 350 + 42\(\frac{6}{7}\)% of 350 = 350 + 150 = 500

Case 2:
M+50 = 350+50 = 400
N+75 = 500+75 = 575
\(\frac{profit}{cost} * 100 = \frac{575-400}{400} * 100 = 43.75\)
Success!

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